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Thanks for the info!

And yes unfortunately none of this is " DIY " in my opinion. If for anything else an electrical fire I highly doubt insurance would approve of your DIY install. I will be seeking an electrician.

For the ProPower onboard I can't seem to find a pdf or manual. My question is do the other 3 120V plugs in the bed work when the 240V is in use? Can they hold seperate ampere loads?
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I guess 7.2 Kw (7200) / 240 V = 30 Amps.

So you can only run 30 amps essentially through the PPO.

Or if you ran everything through 120V outlets you'd get 7200 / 120 = 60 amps?

So could you get "more" electronics plugged in with 120V? I assume extension cord / power strip safety would become an issue here.


I'm a bit embarrassed how little I know about electricity consider it constantly surrounds us.
 

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Yes, all receptacles in the bed are powered. But the total power available is 7.2 KW, mix and match. Your best bet would be to provide backup power to critical loads using the 240V receptacle, and if you need to power any additional random 120V loads, plug them into the cab or frunk receptacles which uses a separate 120V, 20A (2.4 KW) inverter.
 

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I guess 7.2 Kw (7200) / 240 V = 30 Amps.

So you can only run 30 amps essentially through the PPO.

Or if you ran everything through 120V outlets you'd get 7200 / 120 = 60 amps?

So could you get "more" electronics plugged in with 120V? I assume extension cord / power strip safety would become an issue here.


I'm a bit embarrassed how little I know about electricity consider it constantly surrounds us.
Power is the rate at which energy is used = amps times volts.
The 7.2kW limit is for the DC-AC circuitry that powers the bed, including the 240V outlet and the 120V outlets. So any combination of those cannot exceed 7.2kW. Further, the wiring for the 240V outlet is such that is can only provide 30A which would be all the 7.2kW available.

The 120V outlets in the truck are limited to either 15A or 20A depending.

So in the bed there are four 120V outlets, each rated at 20A, but 4 x 15A x 120V = 7.2kW (the limit of the bed DC-AC inverter) so you could not run all of them at the max 20A. But of course if you are using the 240V outlet, some of the available kW is going there. The total cannot exceed the 7.2kW limit of the DC-AC inverter.

I believe there may be two 120V outlets that are rated for 20A (120V x 20A = 2.4kW) and two that are rated at 20A, powered by the other DC-AC inverter which powers the cab and the Frunk outlets. Again, that inverter has a 2.4kW limit which cannot be exceeded, so all the other 120V outlets could not be run at the max current either.

All the outlet have protection circuitry (breakers) that limit their output current, and the inverters also have limiting protection, so if you over load them, they will shut off.

BTW, the battery stores energy which is kWh, that is watts x time.
So power usage times the time that power is being used or stored.

If you want more detail:
------------------------
1 Ampere = 1 coulomb of electric charge moving past a point in 1 second, the unit of electrical current

1 Watt = 1 joule per second (rate of energy transfer) -- A kilowatt (1000 Watts) is a unit of power (rate of flow of energy --Joules-- per unit of time).

1 joule = The work required to move an electric charge of one coulomb through an electrical potential difference of one volt, or one coulomb-volt (C*V): a Joule is a unit of energy

1 joule = The work (energy) required to produce one watt of power for one second, or one watt-second.

1 kWh = 3.6 megajoules (energy delivered by one kilowatt of power for one hour) -- A kilowatt hour is a unit of energy, the product of power and time.

1 volt = the electric potential between two points of a conducting wire when an electric current of one ampere dissipates one watt of power between those points
--the potential difference between two points that will impart one joule of energy per coulomb of charge that passes through it
--the volt is a force, the electromotive force.

1 ohm = the electrical resistance between two points of a conductor when a constant potential difference of one volt (V) applied to these points produces a current of one ampere (A)

EVSE = electric vehicle supply equipment, a device that supplies electrical power for recharging plug-in electric vehicles:

AC Level 1: Connects directly to a standard 120 V North American outlet; capable of supplying 6–16 A (0.7–1.92 kilowatts or "kW") depending on the capacity of a dedicated circuit.

AC Level 2: Utilizes 240 V (single phase) or 208 V (three phase) power to supply between 6 and 80 A (1.4–19.2 kW). It provides a significant charging speed increase over AC Level 1 charging.

DC Level 1: Supplies a maximum of 80 kW at 50–1000 V.

DC Level 2: Supplies a maximum of 400 kW at 50–1000 V.

Charge time can be calculated as:
Battery capacity (kWh) / Charging power (kW)

Charge controller/charge regulator/battery regulator: limits the rate at which electric current is added to or drawn from electric batteries to protect against electrical overload, overcharging, and may protect against over voltage.

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Sorry, I have a MSCEE degree (Masters of Computers and Electrical Engineering) and have taught patent law seminars (also have a JD) and worked as a patent attorney, first admitted to the bar in 1990.
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