ZeusDriver
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- Dec 1, 2025
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- 2022 Lightning
BTW, most of us get about 2.2 miles per kWh at 60 mph.
Also, most of us either have (or have imagined) about 1.0 miles per kWh when towing a medium-sized trailer.
That means that, in the first case, power into the motors is 27.27 kW. Given .93 efficiency, power out of the motors is 34 HP*.
In the second case, power into the motors is 60 kW. Given .93 efficiency, power out of the motors is 74.8 HP.
SO:
If the continuous output of the EREV's engine is 150 HP, and that engine is directly coupled to a .93 efficient generator, then the generator will supply 150*.746 = 111 kW. That means that the duty cycle during towing the load above would be about 54%. Easy-peasy.
If you have found that towing with your Lightning gives you .5 miles per kW, then you might have to hope for a little larger engine in the EREV-- or buy a diesel.
Of course, the engine and generator will also have a peak rating, so it would take a very unusual condition to require the driver to slow down. "Locomotive" is a nebulous term, and the standard towing capability test only requires something like 40 mph, so there is quite a bit of wiggle room, and also quite a bit of room for arguments between marketing and engineering... which is probably what has happened at RAM, resulting in delays in their EREV.
* In the US, and in many other countries, the convention has been to specify motor input power in watts (or kW) and output power in HP. In Europe, engines (such as car and truck engines) are specified in kW, as are electric motors. The reason for the convention in the US is that power calculations for running industrial equipment involve pounds force and speed, with one HP being 550 ft lb/sec. So the mechanical engineer goes to the electrical engineer, and says "I need a 5 HP motor, referring to the motors output (which becomes an input into his machine). Motor efficiency is the ratio of output power to input power, so, for example, a 5 hp motor of average efficiency (.80) will have an input power of 5/.8/*.746 = 4.66kW.
In Europe, when an engineer specifies a 4660 watt motor, the vendor has to ask "Do you mean input power or output power?"
Also, most of us either have (or have imagined) about 1.0 miles per kWh when towing a medium-sized trailer.
That means that, in the first case, power into the motors is 27.27 kW. Given .93 efficiency, power out of the motors is 34 HP*.
In the second case, power into the motors is 60 kW. Given .93 efficiency, power out of the motors is 74.8 HP.
SO:
If the continuous output of the EREV's engine is 150 HP, and that engine is directly coupled to a .93 efficient generator, then the generator will supply 150*.746 = 111 kW. That means that the duty cycle during towing the load above would be about 54%. Easy-peasy.
If you have found that towing with your Lightning gives you .5 miles per kW, then you might have to hope for a little larger engine in the EREV-- or buy a diesel.
Of course, the engine and generator will also have a peak rating, so it would take a very unusual condition to require the driver to slow down. "Locomotive" is a nebulous term, and the standard towing capability test only requires something like 40 mph, so there is quite a bit of wiggle room, and also quite a bit of room for arguments between marketing and engineering... which is probably what has happened at RAM, resulting in delays in their EREV.
* In the US, and in many other countries, the convention has been to specify motor input power in watts (or kW) and output power in HP. In Europe, engines (such as car and truck engines) are specified in kW, as are electric motors. The reason for the convention in the US is that power calculations for running industrial equipment involve pounds force and speed, with one HP being 550 ft lb/sec. So the mechanical engineer goes to the electrical engineer, and says "I need a 5 HP motor, referring to the motors output (which becomes an input into his machine). Motor efficiency is the ratio of output power to input power, so, for example, a 5 hp motor of average efficiency (.80) will have an input power of 5/.8/*.746 = 4.66kW.
In Europe, when an engineer specifies a 4660 watt motor, the vendor has to ask "Do you mean input power or output power?"
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