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Power Leakage from DC Power Supply

richguy82

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I am trying to use an 850 watt DC power supply plugged into the bed ProPower outlet. I have a watt meter on this cord and it says it’s pulling just under 900 watts. When I go into my truck it says it’s pulling 1400! Any idea what this is? Does this value include the fans inside the truck potentially trying to cool the inverter?
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I am trying to use an 850 watt DC power supply plugged into the bed ProPower outlet. I have a watt meter on this cord and it says it’s pulling just under 900 watts. When I go into my truck it says it’s pulling 1400! Any idea what this is? Does this value include the fans inside the truck potentially trying to cool the inverter?
No, it doesn't include the truck itself running fans.
 

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Clamp on an amp meter and see how much current is flowing
 

K6CCC

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My guess is that the power supply is a VERY non power factor corrected power supply. What that means is that the current does not follow the voltage. This is common on DC power supplies. A Real or True RMS multimeter can handle that and correctly display the actual power. Many meters can not. Never measured the Lightning's ability to deal with seriously non PF loads, but it would not surprise me to find that it reads the power poorly. Pretty sure I have seen the same issue.
 
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richguy82

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jetfixr1

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If you have a harbor freight around theyre usually around $30-$45. Cheap and will give you a somewhat close reading.
I don’t have one of those unfortunately.
 
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richguy82

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My guess is that the power supply is a VERY non power factor corrected power supply. What that means is that the current does not follow the voltage. This is common on DC power supplies. A Real or True RMS multimeter can handle that and correctly display the actual power. Many meters can not. Never measured the Lightning's ability to deal with seriously non PF loads, but it would not surprise me to find that it reads the power poorly. Pretty sure I have seen the same issue.
Interesting. So you think the Lightning is confused by this power supply? I mean it’s a cheap power supply for sure. The watt meter is reading as I would expect as it’s losing roughly 7% due to the fan and whatever else.
 

K6CCC

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OK, let me explain this a bit. Warning, this will get technical.

When dealing with Alternating Current ( AC ) power, the voltage wings back and forth many times per second - 120 times per second in each direction in the US for 60 complete cycles per second. For 120 volt AC power, that cycle varies from about 165 volts positive to 165 volts negative in reference to the neutral wire. It follows a sinusoidal curve - also known for this discussion as a sine wave. In a purely resistive load (a heating element for example), the current exactly follows the voltage. However very few things are a purely resistive load. If the load is somewhat capacitive or inductive (motors for example), the current leads or follows the voltage. A simple wattmeter can't handle the current and voltage peaks not being at the same time and will give inaccurate readings. A good True RMS (Root Mean Squared) watt meter knows how to handle the time difference. This is not exactly what is happening with your cheap DC power supply, but it gives some background.

With a simple AC operated DC power, the voltage supplied to the power supply is still following the sine wave, but the current is radically different. What happens is that all the current flows during a small percentage of time (when the voltage is near peak), and for the rest of the sine wave, there is almost zero current flow. Because the current is flowing only for a very small percentage of time, the peak current really high. Most meters have fits over that and give quite inaccurate readings. Good DC power supplies have additional circuitry to correct for this peak current issue - called power factor correction. But that costs extra money so cheap power supplies generally do not have this additional circuitry. For most purposes, the peak current is not a major problem, but especially when the power source is a small generator or inverter, it can really cause problems. One of the issues is that if you have an inverter that is paying attention to the peak current (such as our Lightnings), it can trip off on overcurrent, even though the total wattage is well under the limit. That is the exact situation I mentioned in my earlier post where I had the Lightning inverters trip off even though I knew the total wattage was well under the limits.

If you want a longer explanation about power factor, you can check out: https://en.wikipedia.org/wiki/Power_factor
 

chl

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I am trying to use an 850 watt DC power supply plugged into the bed ProPower outlet. I have a watt meter on this cord and it says it’s pulling just under 900 watts. When I go into my truck it says it’s pulling 1400! Any idea what this is? Does this value include the fans inside the truck potentially trying to cool the inverter?
K6CCC explained it - it is the power factor of the DC power supply having an effect on the watt meter in part.

The following might clarify it from a mathematical point of view:

Ford F-150 Lightning Power Leakage from DC Power Supply power factor watt meter


From: https://testbook.com/question-answe...a-wattmeter-when-th--666d94691201eeeeb0bd9f67

So your circuit, the power supply, may have a leading power factor due to it being a partly capacitive load on the Lightning output - the current peaks before the voltage.

Ford F-150 Lightning Power Leakage from DC Power Supply capacitive load

From: https://eepower.com/technical-artic...-much-electricity-your-power-system-consumes/

In reactive loads, the power factor is not one (it is less than 1), so the real power is less than it would be in a purely resistive load.

Both the Lightning and the watt meter are "correct" regarding real power.
The Lightning says it is supplying 1400W which it is.

The watt meter says the load is using just under 900W which it is.
That is the real power being used by the resistive components of the power supply, including the voltage drops of the rectifier transistors, for example.

There is some power being stored by the reactance which accounts for some of the difference as well.

The better the power supply the closer to one the power factor is.
 
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richguy82

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K6CCC explained it - it is the power factor's effect on the watt meter.

The following might clarify it from a mathematical point of view:

power factor watt meter.jpg


From: https://testbook.com/question-answe...a-wattmeter-when-th--666d94691201eeeeb0bd9f67

So your circuit, the power supply, has a leading power factor due to it being a capacitive load on the Lightning output - the current peaks before the voltage.

capacitive load.jpg

From: https://eepower.com/technical-artic...-much-electricity-your-power-system-consumes/
I appreciate the attempts to educate on this, but I have to pull my layman card on this one 😆. I was trying to charge a power station using a DC power supply powered by the truck. Power station was showing 850 in, 900 watts on the meter, and 1400 in the truck. For clarification, assuming the power station knows what it’s getting, am I actually seeing a 500 watt loss by using this inverter? If there is this much loss, I will likely stop use this power supply going forward.
 
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K6CCC

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No, there is not that much loss. If it were, you would not be able to touch it because it would be massively HOT. It's a metering difference / difficulty caused by a crappy power factor. And as I pointed out earlier, it's not just the capacitive load, but the very likely seriously non-sinusoidal current. In the drawing below, the only time that the power supply is drawing current is during the portion of time where the dark line is sloping up (where my red arrows are).

Ford F-150 Lightning Power Leakage from DC Power Supply DC Power supply current
 

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Ah, the non-sinusoidal current! I hate that!
 

chl

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I appreciate the attempts to educate on this, but I have to pull my layman card on this one 😆. I was trying to charge a power station using a DC power supply powered by the truck. Power station was showing 850 in, 900 watts on the meter, and 1400 in the truck. For clarification, assuming the power station knows what it’s getting, am I actually seeing a 500 watt loss by using this inverter? If there is this much loss, I will likely stop use this power supply going forward.
The power factor essentially causes some input power to be "lost" to the reactive loads (inductors/transformer and/or capacitors) and a power factor of 1 results in the most power transferred.

A good DC power supply should not behave like a very reactive load and have good power factor compensation circuitry within to make its power factor as close to 1 as possible.

Assuming the Lightning is reporting real power as "1400W" supplied to the DC power supply input, and the power supply is only supplying 900W at its output, the DC power supply is likely behaving like a partly reactive load so some power is being "lost" as a result of internal resistance and the reactivity.

The power supply's efficiency seems to be 900/1400 x 100 or 64%.

That is typical of linear power supplies (transformer-rectifier-capacitor filter-regulator-output capacitor) which have a power factor in the .6 to .7 range.
 
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chl

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On the plus side, linear power supplies are simple, noise free and less expensive, if less efficient.
So probably a good fit for some applications involving electronic sensitive circuitry.
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